Question

How do you find the slope of a line passing through (11, -2) and (2, -2)?

Answer 1

`m=(Deltay)/(Deltax)` where the `Delta`'s stand for "change in".

Explanation:

`m=(y_2-y_1)/(x_2-x_1)=(-2-(-2))/(2-11)=0/(-9)=0`

Note:
We could have seen this earlier, because both `y` values are the same, so there is no change. In other words: this is a horizontal line (slope=0) with the equation `y=-2`.
graph{0x-2 [-7.96, 12.04, -4.64, 5.36]}