# How do you find the slope of a line perpendicular to 2y = -6x + 8?

We first simplify by dividing everything by $2$:
$\to y = - 3 x + 8$
The slope is now $- 3$
The slope of a perpendicular line is the negative inverse of the first slope, in other words, they multiply to give $- 1$:
$\left(- 3\right) \times m = - 1 \to m = \frac{- 1}{-} 3 = \frac{1}{3}$