# How do you find the slope of the line whose equation is x - 6y + 12 = 0?

Convert the equation in the standard form $y = m x + q$. Once these manipulations are done, you'll have that the slope is $m$.
So, starting from $x - 6 y + 12 = 0$, add $6 y$ at both sides, to get $x + 12 = 6 y$. From here, divide both sides by 6, and you have
$\frac{x}{6} + 2 = y$, which of course is equal to
$y = \frac{1}{6} x + 2$.
So, $m = \frac{1}{6}$ and $q = 2$ (which is actually irrelevant from your point of view. The slope is thus $\frac{1}{6}$.