Question

How do you find the slope of the secant lines of `f(x)=6.1x^2-9.1x` through the points: x=8 and x=16?

Answer 1

137.3

Explanation:

`f(8)=(6.1)(64)-(9.1)(8)=317.6`. This point is (8, 317.6).

`f(16)=(6.1)(256)-(9.1)(16)=1416`. This point is (16, 1416).

The slope of the secant line joining these two points
=`(1416-317.6)/(16-8)=137.3`