Question

How do you find the slope of the tangent line to the graph of `f(x)=x^2/(x+1)` at (2, 4/3)?

Answer 1

`8/9`

Find f'(x) = `(2x(x+1)-x^2 *1)/(x+1)^2`

=`(x^2+2x)/((x+1)^2`

At x=2, f'(x)= 8/9