# How do you find the slope of the tangent line to the graph of f(x)=x^2/(x+1) at (2, 4/3)?

$\frac{8}{9}$
Find f'(x) = $\frac{2 x \left(x + 1\right) - {x}^{2} \cdot 1}{x + 1} ^ 2$
=(x^2+2x)/((x+1)^2