How do you find the slope that is perpendicular to the line -6x -8y = 86x8y=8?

2 Answers
Aug 4, 2016

=4/3=43

Explanation:

y=mx+cy=mx+c where mm is the slope
-6x-8y=86x8y=8
or
8y=-6x-88y=6x8
or
y=-6x/8-8/8y=6x888
or
y=-3x/4-1y=3x41
So the slope is m=-3/4m=34 of the above lineSo the slope of the line that is perpendicular to the above line=m1=-1/m=4/3=m1=1m=43

Aug 4, 2016

m_2=4/3m2=43

Explanation:

-6x-8y=86x8y=8

"rearrange the equation -6x-8y=8 as :"rearrange the equation -6x-8y=8 as :

8y=-6x-88y=6x8

y=-6/8x-8/8y=68x88

y=color(red)(-3/4)x-1y=34x1

"slope of the line is "-3/4slope of the line is 34

"the lines are perpendicular if product of their slopes are equal to -1"the lines are perpendicular if product of their slopes are equal to -1

m_1*m_2=-1m1m2=1

-3/4*m_2=-134m2=1

m_2=4/3m2=43

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