How do you find the slope that is perpendicular to the line #-6x -8y = 8#?

2 Answers
Aug 4, 2016

Answer:

#=4/3#

Explanation:

#y=mx+c# where #m# is the slope
#-6x-8y=8#
or
#8y=-6x-8#
or
#y=-6x/8-8/8#
or
#y=-3x/4-1#
So the slope is #m=-3/4# of the above lineSo the slope of the line that is perpendicular to the above line#=m1=-1/m=4/3#

Aug 4, 2016

Answer:

#m_2=4/3#

Explanation:

#-6x-8y=8#

#"rearrange the equation -6x-8y=8 as :"#

#8y=-6x-8#

#y=-6/8x-8/8#

#y=color(red)(-3/4)x-1#

#"slope of the line is "-3/4#

#"the lines are perpendicular if product of their slopes are equal to -1"#

#m_1*m_2=-1#

#-3/4*m_2=-1#

#m_2=4/3#

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