Question

How do you find the smallest perimeter and the dimensions for a rectangle with an area of `64` `i n^2`?

Answer 1

`perimeter = 32` in.

Explanation:

A square has the smallest perimeter of any rectangle with a given area.

Let the side of the square be `x`
`=> x^2=64`
`=> x=+-sqrt64=+-8, => x=8`

perimeter `=8xx4=32` in.