# How do you find the sum given Sigma 1/j from j=3 to 5?

${\sum}_{j = 3}^{5} \frac{1}{j} = \frac{47}{30}$
${\sum}_{j = 3}^{5} \frac{1}{j} = \frac{1}{3} + \frac{1}{4} + \frac{1}{5}$
$\therefore {\sum}_{j = 3}^{5} \frac{1}{j} = \frac{20 + 15 + 12}{60}$
$\therefore {\sum}_{j = 3}^{5} \frac{1}{j} = \frac{47}{30}$