# How do you find the value of 4+64 div(8times4)div2?

$5$
$4 + 64 \div \left(8 \times 4\right) \div 2 = 4 + 64 \div 32 \div 2$
$4 + 64 \div 32 \div 2 = 4 + 1 = 5$