Question

How do you find the value of `cos((16pi)/3)`?

Answer 1

`- 1/2`

Explanation:

Use trig table of special arcs and unit circle -->
#cos ((16pi)/3) = cos ((-2pi)/3 + (18pi)/3) = cos ((-2pi)/3 + 6pi) = cos ((-2pi)/3) = cos ((2pi)/3) = - 1/2#