Question

How do you find the value of `tan(tan^-1(8/pi))`?

Answer 1

`tan(arctan(8/pi)) = 8/pi`

Explanation:

Assuming that `tan^-1(x)` is the `arctan(x)`, that is, the inverse tangent function, we know that by axiom

`tan(arctan(x)) = x`, therefore `tan(arctan(8/pi)) = 8/pi`