# How do you find the value of the discriminant and state the type of solutions given -9b^2=-8b+8?

Jun 30, 2017

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#### Explanation:

If $a {x}^{2} + b x + c = 0$
Then discriminant$=$${b}^{2} - 4 \left(a\right) \left(c\right)$
If discriminant$> 0$, then solutions are two different real roots
If discriminant $= 0$, then solutions are two equal real roots
If discriminant$< 0$, then there are no real roots for solutions

$- 9 {b}^{2} = - 8 b + 8$
$9 {b}^{2} - 8 b + 8 = 0$
$= {\left(- 8\right)}^{2} - 4 \left(9\right) \left(8\right)$
$= 64 - 288$
$= - 224$