# How do you find the values of theta given cottheta=sqrt3/3?

Dec 25, 2016

$\frac{\pi}{6} + k \pi$

#### Explanation:

$\cot t = \frac{1}{\tan t} = \frac{\sqrt{3}}{3}$
$\tan t = \frac{3}{\sqrt{3}} = \sqrt{3}$
Trig table and unit circle -->
$\tan t = \sqrt{3}$ --> $t = \frac{\pi}{6}$ and $t = \frac{\pi}{6} + \pi = \frac{7 \pi}{6}$
$t = \frac{\pi}{6} + k \pi$