# How do you find the values of theta given tantheta=sqrt3?

Aug 5, 2017

$\theta = \frac{\pi}{3} + n \pi , n \in \mathbb{Z}$

#### Explanation:

$\text{given } \tan \theta = \sqrt{3}$

$\Rightarrow \theta = {\tan}^{-} 1 \left(\sqrt{3}\right) = \frac{\pi}{3}$

$\text{since the tangent function is periodic}$

$\text{we can generalise the solution as}$

$\theta = \frac{\pi}{3} + n \pi , n \in \mathbb{Z}$