# How do you find the values of w, x, y, and z given -2[(w+5, x-z), (3y, 8)]=[(-16, -4), (6, 2x+8z)]?

Dec 29, 2016

#### Answer:

$w = 3$

$y = - 1$

$z = - 2$

$x = 0$

#### Explanation:

First you can divide both of sides by -2 an then you can get the following four relations:

1) $w + 5 = 8$;

2) $3 y = - 3$;

3) $x - z = 2$;

4) $8 = - x - 4 z$

Then

1) $w = 3$

2) $y = - 1$

By summing 3) and 4), you get:

$\cancel{x} - z \cancel{- x} - 4 z = 2 + 8$

$- 5 z = 10$

3) $z = - 2$

4) $x = z + 2 = 0$