# How do you find the vertex and axis of symmetry of y=x^2+2x-1?

May 6, 2016

see below

#### Explanation:

Axis of symmetric=$- \frac{b}{2 a}$=$- \frac{2}{2 \left(1\right)}$=$- 1$

To find value of y, substitute value of x into equation.

$y = {\left(- 1\right)}^{2} + 2 \left(- 1\right) - 1$=$- 2$

Vertex of symmetric is $\left(- 1 , - 2\right)$