Question

How do you find the vertex and axis of symmetry of `y=x^2+8x-7`?

Answer 1

y = x^2 + 8x - 7

Ans: Vertex (-4, -23)

Explanation:

x-coordinate of vertex or axis of symmetry:
`x = (-b)/(2a) = -9/2 = -4`
y-coordinate of vertex:
`y = y(-4) = 16 - 32 - 7 = -23`
graph{x^2 + 8x - 7 [-80, 80, -40, 40]}