# How do you find the vertex and intercepts for #f(x)=3(x-2)^2+1 #?

##### 1 Answer

Vertex: (2,1)

x-intercepts: None

y-intercept: (0,13)

#### Explanation:

The quadratic given is already in vertex form, so finding the vertex is relatively simple:

In this case:

To find the intercepts, we need to convert to standard form by evaluating the right hand side:

The y-intercept is simply

We can use the quadratic formula to find the x-intercepts:

And here we reach a problem, because the numerator contains an imaginary number (