How do you find the vertex and intercepts for #f(x)=3(x-2)^2+1 #?
The quadratic given is already in vertex form, so finding the vertex is relatively simple:
In this case:
To find the intercepts, we need to convert to standard form by evaluating the right hand side:
The y-intercept is simply
We can use the quadratic formula to find the x-intercepts:
And here we reach a problem, because the numerator contains an imaginary number (