# How do you find the vertex and intercepts for #x^2-4x+y+3=0#?

##### 1 Answer

Jun 8, 2018

See graph

#### Explanation:

first put in standard form:

y-intercept, set

x-intercept(s) if they exist, set

factor:

Axis of Symmetry (aos) in the form

Finally find the vertex it is a minimum if

graph{-x^2+4x-3 [-7.21, 12.79, -8.2, 1.8]}