Question

How do you find the vertex and intercepts for `y = x^2 – 10x + 5`?

Answer 1

Vertex `(5, -20)`
Intercept `=5`

Explanation:

Vertex

`x=(-b)/(2a)=(-(-10))/(2 xx 1)=10/2=5`

At `x=5`

`y=5^2-10(5)+5=25-50+5=30-50=-20`

Vertex `(5, -20)`
Intercept `=5`