# How do you find the vertex and intercepts for #y = x^2 - 8#?

##### 1 Answer

vertex =

y-intercept =

x-intercepts =

#### Explanation:

The general equation for a quadratic function in vertex form is:

#y = a(x-h)^2+k#

With this equation,

#y=1(x-0)^2-8#

The vertex of a quadratic equation in vertex form is

To find the y-intercept, substitute

#y=x^2-8#

#y=(0)^2-8#

#y=(0)-8#

#y=-8#

To find the x-intercept, substitute

#y=x^2-8#

#0=x^2-8#

#8=x^2#

#x=+-sqrt(8)#

#x=2sqrt(2)# or#-2sqrt(2)#

#x=2.83# or#-2.83#

Here is a graph of the equation:

graph{y= x^2-8 [-12.78, 12.53, -11.14, 2.05]}

As you can see, the graph has a y-intercept of