How do you find the vertex and intercepts for #y = (x – 3)^2 + 4#?
We use the equation.
Luckily for you, the equation is already in perfect vertex form. Therefore, it's an easy matter to find the vertex. Stated simply, the vertex of this equation can be found by taking the negative of the number inside of the parenthesis (so the negative of -3) as the x coordinate, and the normal value of the number outside of the parenthesis (so 4) and making a point out of them. Since the negative of -3 is 3, your point is:
That is stated simply. If you were to graph it, you would have to transform the parabola from its original mother function (x^2) to the right three and up 4 on the y axis.
To find the x intercept, plug in 0 for y and solve the equation by isolating x, to find the y intercept plug in 0 for x and solve b isolating y.
Hope this helps!