Question

How do you find the vertex and the intercepts for `f(x) = -5(x+5)^2 + 7`?

Answer 1

Vertex (-5, 7)

Explanation:

This is the vertex form of a function:
x-coordinate of vertex --> x = -5
y-coordinate of vertex --> y = 7
To find y intercept, make x = 0 --> y = -125 + 7 = -118
To find x-intercepts, make y = 0 --> `5(x) 5)^2 = 7`
`(x + 5)^2 = 7/5`
`(x + 5) = +- sqrt7/sqrt5`
`x = - 5 +- sqrt7/sqrt5`