# How do you find the vertex and the intercepts for f(x) = -5(x+5)^2 + 7?

Mar 11, 2016

Vertex (-5, 7)

#### Explanation:

This is the vertex form of a function:
x-coordinate of vertex --> x = -5
y-coordinate of vertex --> y = 7
To find y intercept, make x = 0 --> y = -125 + 7 = -118
To find x-intercepts, make y = 0 --> 5(x) 5)^2 = 7
${\left(x + 5\right)}^{2} = \frac{7}{5}$
$\left(x + 5\right) = \pm \frac{\sqrt{7}}{\sqrt{5}}$
$x = - 5 \pm \frac{\sqrt{7}}{\sqrt{5}}$