# How do you find the vertex and the intercepts for #f(x)=x^2+x-2#?

##### 2 Answers

#### Explanation:

x-coordinate of vertex:

y-coordinate of vertex:

To find y-intercept, make x = 0 --> y = -2

To find x-intercepts, make t = 0, and solve the quadratic equation:

Since a + b + c = 0, use shortcut. The 2 x-intercepts (real roots) are:

1 and

x int:

y int:

#### Explanation:

In a quadratic equation like

So,

To find the

To find the