How do you find the vertex and the intercepts for #f(x)=x^2+x-2#?
x-coordinate of vertex:
y-coordinate of vertex:
To find y-intercept, make x = 0 --> y = -2.
To find x-intercepts, make y = 0 and solve the quadratic equation
Since a + b + c = 0, use shortcut.
The 2 real roots are 1 and