How do you find the vertex and the intercepts for #y= 2x^2 - 4x + 7#?
The vertex is (1,5) and there are no real intercepts.
The x-coordinate of the vertex can be found using
So 1 would be the x-coordinate of the vertex. You would then plug this in for x in the original equation:
To find the intercepts it would be best to use quadratic formula:
When we solve under the square root we can already see that we will get