How do you find the vertex and the intercepts for #y=x^2+6x-5#?
1 Answer
Mar 13, 2016
vertex
Y- Intercept
Explanation:
Given -
#y = x^2+6x-5#
Find the vertex
#x=(-b)/(2a)=(-6)/(2 xx1)=-6/2=-3#
Find
#y=(-3)^2+6(-3)-5#
#y=9-18-5#
#y=9-23#
#y=-14#
vertex
Put
#y=0^2+6(0)-5#
#y=-5#
Y- Intercept >#(0, -5)#