How do you find the vertex and the intercepts for y=-x^2+8x+16?
1 Answer
Apr 26, 2016
Vertex
Y-Intercept
Explanation:
Given -
y=-x^2+8x+16
Vertex
x=(-b)/(2a)=(-8)/(2 xx (-1))=(-8)/(-2)=4
Atx=4 ; y=-(4^2)+8(4)+16
y=-16+32+16=32
Vertex
Y-Intercept
At
Y-Intercept