# How do you find the vertex for y=x^2-4?

Jun 27, 2018

$\left(0 , - 4\right)$

#### Explanation:

To find the vertex of a standard quadratic equation $y = a {x}^{2} + b x + c$, first use the formula $\frac{- b}{2 a}$ to find the $x$-coordinate of the vertex:
$x = \frac{- b}{2 a} = \frac{- 0}{2 \left(1\right)} = 0$

Now plug the $x$ value of the vertex back into the equation to find the $y$ value:
$y = {\left(0\right)}^{2} - 4 = - 4$

Therefore, the vertex is at $\left(0 , - 4\right)$.

Hope this helps!