# How do you find the vertex of -20(y+5)=(x+9)^2?

Sep 30, 2017

$\text{vertex } = \left(- 9 , - 5\right)$

#### Explanation:

$\text{using the translated form of the equation of a parabola}$

•color(white)(x)(x-h)^2==4p(y-k)

$\text{where the vertex } = \left(h , k\right)$

${\left(x + 9\right)}^{2} = - 20 \left(y + 5\right) \text{ is in this form }$

$\text{with "h=-9" and } k = - 5$

$\Rightarrow \textcolor{m a \ge n t a}{\text{vertex }} = \left(- 9 , - 5\right)$