Question

How do you find the VERTEX of a parabola `f(x)= -3x^2-6x-7`?

Answer 1

Find vertex of f(x) = - 3x^2 - 6x - 7

Vertex (-1, -4)

Explanation:

x-coordinates of vertex
`x = (-b/2a) = 6/-6 = - 1`
y coordinate of vertex:
y = f(-1) = -3 + 6 - 7 = - 4