Question

How do you find the VERTEX of a parabola `y= -3(x+2)^2+5`?

Answer 1

When written in this form, the vertex is easy to find.

Explanation:

This happens when the function is at its maximum or minimum, which happens when the square part `(x+2)^2=0->x=-2`.
Then `y=5`. So the vertex is `(-2,5)`
graph{-3(x+2)^2+5 [-12.035, 7.964, -3.6, 6.4]}