# How do you find the VERTEX of a parabola y= -3(x+2)^2+5?

This happens when the function is at its maximum or minimum, which happens when the square part ${\left(x + 2\right)}^{2} = 0 \to x = - 2$.
Then $y = 5$. So the vertex is $\left(- 2 , 5\right)$