How do you find the vertex of a parabola y=-[x]^2+1?

1 Answer
Jul 18, 2015

The vertex is at color(red)((0,1).

Explanation:

y = -x^2+1

The standard form of the equation for a parabola is

y = ax^2+bx+c, so

a = -1, b = 0, c = 1

The x-coordinate is at x = -b/(2a) = -0/(2(-1)) = 0

To find the y-coordinate of the vertex, substitute x =0 into the equation to get

y = -(0)^2 +1 = 0+1 = 1

The vertex is at (0,1).

graph{-x^2+1 [-3, 3, -5, 2]}