# How do you find the vertex of a parabola y=[x-3]^2+10?

The vertex of $y = {\left[x - 3\right]}^{2} + 10$ is at $\left(3 , 10\right)$
$\textcolor{w h i t e}{\text{XXXX}}$$y = {\left(x - a\right)}^{2} + b$
is in "vertex form" with a vertex at $\left(a , b\right)$