# How do you find the vertex of f(x)=2(x-3)^2+1?

Feb 21, 2017

vertex: color(green)(""(3,1))

#### Explanation:

The general quadratic vertex form is
$\textcolor{w h i t e}{\text{XXX}} f \left(x\right) = \textcolor{\mathmr{and} a n \ge}{m} {\left(x - \textcolor{red}{a}\right)}^{2} + \textcolor{b l u e}{b}$
with vertex at $\left(\textcolor{red}{a} , \textcolor{b l u e}{b}\right)$

$\textcolor{w h i t e}{\text{XXX}} f \left(x\right) = \textcolor{\mathmr{and} a n \ge}{2} {\left(x - \textcolor{red}{3}\right)}^{2} + \textcolor{b l u e}{1}$
with vertex at $\left(\textcolor{red}{3} , \textcolor{b l u e}{1}\right)$