How do you find the vertex of #f(x)= x^2+10x-8#?

1 Answer
Jun 30, 2018

#"vertex "=(-5,-33)#

Explanation:

#"the equation of a parabola in "color(blue)"vertex form"# is.

#•color(white)(x)y=a(x-h)^2+k#

#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#

#"to obtain this form use "color(blue)"completing the square"#

#y=x^2+2(5)xcolor(red)(+25)color(red)(-25)-8#

#color(white)(y)=(x+5)^2-33larrcolor(blue)"in vertex form"#

#color(magenta)"vertex "=(-5,-33)#