Question

How do you find the vertex of the parabola: `y=x^2+4x-5`?

Answer 1

Find the vertex of y = x^2 + 4x - 5.

Ans: (-2, -9)

Explanation:

x-coordinate of the vertex:
`x = (-b/2a) = -4/2 = -2`
y-coodinate of vertex: `y = f(-2) = (-2)^2 + 4(-2) - 5 = 4 - 8 - 5 = -9`