# How do you find the vertex of the parabola: y=x^2+4x-5?

$x = \left(- \frac{b}{2} a\right) = - \frac{4}{2} = - 2$
y-coodinate of vertex: $y = f \left(- 2\right) = {\left(- 2\right)}^{2} + 4 \left(- 2\right) - 5 = 4 - 8 - 5 = - 9$