# How do you find the vertex of this parabola y=-x^2-2x-5?

##### 1 Answer
Nov 3, 2016

Please read the explanation for the steps leading to the vertex $\left(1 , - 8\right)$

#### Explanation:

For an equation of a parabola of the form $y = a {x}^{2} + b x + c$, the x coordinate, h, of the vertex is:

$h = - \frac{b}{2 a}$

In the given equation, $a = - 1 , \mathmr{and} b = - 2$, therefore:

$h = \frac{- 2}{2 \left(- 1\right)}$

$h = 1$

To obtain the y coordinate of the vertex, evaluate the function at h:

$y = - {\left(1\right)}^{2} - 2 \left(1\right) - 5$

$y = - 8$

The vertex is at the point $\left(1 , - 8\right)$