# How do you find the vertex of y = x^2 - 2?

The vertex form is $y = a \cdot {\left(x - h\right)}^{2} + k$ hence for $y = {x}^{2} - 2$ is
$a = 1 , h = 0 , k = - 2$
So the vertex is $\left(h , k\right) = \left(0 , - 2\right)$