# How do you find the vertex of y= -x^2+ 4x + 2?

Dec 27, 2017

$- {\left(x - 2\right)}^{2} + 6$

#### Explanation:

−x^2+4x+2

$\implies - 1 \cdot \left[{x}^{2} - 4 x - 2\right]$

$\implies - 1 \cdot \left[\left({x}^{2} - 2 \cdot 2 x + {2}^{2}\right) - {2}^{2} - 2\right]$

$\implies - 1 \cdot \left[{\left(x - 2\right)}^{2} - 4 - 2\right]$

$\implies - 1 \cdot \left[{\left(x - 2\right)}^{2} - 6\right]$

(-(x-2)^2+6)/