# How do you find the vertical asymptotes and holes of #f(x)=(x^2+4x+3)/(x+3)#?

##### 1 Answer

Nov 16, 2016

There are no asymptotes, only a hole at

#### Explanation:

Let's factorise the numerator

Therefore,

There we have a hole at

graph{(x^2+4x+3)/(x+3) [-7.316, 6.73, -5.28, 1.743]}