# How do you find the vertical, horizontal and slant asymptotes of: (2x-1)/(x^2+3x)?

Apr 30, 2016

#### Answer:

vertical asymptotes x = -3 , x = 0
horizontal asymptote y = 0

#### Explanation:

Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation/s set the denominator equal to zero.

solve : x^2+3x=0 → x(x+3)=0 → x = 0 , x = -3

$\Rightarrow x = - 3 \text{ and " x=0" are the asymptotes }$

Horizontal asymptotes occur as ${\lim}_{x \to \pm \infty} , f \left(x\right) \to 0$

If the degree of the numerator < degree of denominator , as is the case here numerator (degree 1) and denominator (degree 2) then the equation is always y = 0

Slant asymptotes occur when the degree of the numerator > degree of the denominator. This is not the case here hence there are no slant asymptotes.
graph{(2x-1)/(x^2+3x) [-10, 10, -5, 5]}