# How do you find the vertical, horizontal and slant asymptotes of: #(8x^2-x+2)/(4x^2-16)#?

##### 1 Answer

Nov 7, 2016

Vertical asymptotes:

Horizontal asymptote:

No slant asymptotes, as slant asymptotes only occur when the degree on the numerator is greater than the degree on the denominator.

#### Explanation:

Let

**Vertical Asymptotes:**

First, factor as much as possible. The numerator cannot be factored. The denominator can be factored into

Vertical asymptotes occur when the denominator is equal to zero. In this case, that is when

**Horizontal Asymptote:**

Horizontal asymptotes are the value that the function approaches when the x value approaches