# How do you find the vertical, horizontal or slant asymptotes for #200/(1+10(e^(-0.5x)))#?

##### 1 Answer

Dec 6, 2016

#### Answer:

Two horizontal asymptotes:

#### Explanation:

y-intercept ( x = 0 ):

See zoomed graphs for clarity.

graph{y(1+10e^(-.5x))-200=0 [-660, 659.5, -330, 329.5]}

graph{y(1+10e^(-.5x))-200=0 [-41.26, 41.2, -20.7, 20.52]}