Question

How do you find the vertical, horizontal or slant asymptotes for `200/(1+10(e^(-0.5x)))`?

Answer 1

Two horizontal asymptotes: `y = 0 larr and y=100rarr`

Explanation:

`0<=y<=200`

y-intercept ( x = 0 ): `200/11=18.18`, nearly.

`y to 0`, as, `x to oo and y to 200`, as `x to -oo`.

See zoomed graphs for clarity.

graph{y(1+10e^(-.5x))-200=0 [-660, 659.5, -330, 329.5]}

graph{y(1+10e^(-.5x))-200=0 [-41.26, 41.2, -20.7, 20.52]}