# How do you find the vertical, horizontal or slant asymptotes for #(4x^2+11) /( x^2+8x−9)#?

##### 1 Answer

Dec 27, 2016

#### Answer:

The vertical asymptotes are

No slant asymptote.

The horizontal asymptote is

#### Explanation:

Let's factorise the denominator

Let,

The domain of

As we cannot divide by

So, the vertical asymptotes are

The degree of the numerator is

To find the horizontal asymptote, we compute the limits of

The horizontal asymptote is

graph{(y-(4x^2+11)/(x^2+8x-9))(y-4)(x-1)(x+9)=0 [-52, 52, -26, 26]}