# How do you find the vertical, horizontal or slant asymptotes for f(x)= 1/x^2?

Aug 8, 2018

Vertical asymptote is at $x = 0$ ,horizontal asymptote is at $y = 0$ (x axis).

#### Explanation:

$f \left(x\right) \mathmr{and} y = \frac{1}{x} ^ 2$

Vertical asymptote occur when denominator is zero.

 x^2=0 :. x=0; lim(x->0^-) ,y -> (+oo)

$\lim \left(x \to {0}^{+}\right) , y \to \left(+ \infty\right)$

Vertical asymptote is at $x = 0$

Horizontal asymptote: lim (x->+-oo) ; y =0

Horizontal asymptote is at $y = 0$ (x axis)

If the numerator's degree is greater (by a margin of 1), then we

have a slant asymptote , so there is no slant asymptote.

graph{1/x^2 [-10, 10, -5, 5]}[Ans]