How do you find the vertical, horizontal or slant asymptotes for #f(x)= 1/x^2#?

Question

1425 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-08T12:40:16

Vertical asymptote is at #x=0# ,horizontal asymptote is at # y=0 # (x axis).

#f(x) or y=1/x^2#

Vertical asymptote occur when denominator is zero.

# x^2=0 :. x=0; lim(x->0^-) ,y -> (+oo) #

#lim (x->0^+), y -> (+oo) #

Vertical asymptote is at #x=0#

Horizontal asymptote: #lim (x->+-oo) ; y =0#

Horizontal asymptote is at # y=0 # (x axis)

If the numerator's degree is greater (by a margin of 1), then we

have a slant asymptote , so there is no slant asymptote.

graph{1/x^2 [-10, 10, -5, 5]}[Ans]