# How do you find the vertical, horizontal or slant asymptotes for #f(x) = (x+1) / (x+2)#?

##### 1 Answer

#### Answer:

Vertical :

#### Explanation:

degree lesser than that of S.

{x = a zero of S} gives vertical asymptotes.

Here,

Interestingly,

So, this represents a hyperbola with asymptotes

and so, the hyperbola is rectangular.

See this with asymptotes, in the Socratic graph.

graph{((y-1)(x+2)+1)(y-1+.001x)(x+2+.001y)=0x^2 [-10, 10, -5, 5]}