How do you find the vertical, horizontal or slant asymptotes for #(x + 1 )/( 2x - 4)#?

1 Answer
Feb 28, 2016

Answer:

vertical asymptote x = 2
horizontal asymptote #y = 1/2 #

Explanation:

Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation let the denominator equal zero.

solve : 2(x-2) = 0 → x = 2 is the equation.

Horizontal asymptotes occur as #lim_(x→±∞) f(x) → 0#

If the degree of the numerator and denominator are equal , as in this case , both degree 1 then the equation can be found by taking the ratio of leading coefficients.

#rArr " equation is " y = 1/2 #
Here is the graph of the function to illustrate them
graph{(x+1)/(2x-4) [-10, 10, -5, 5]}