# How do you find the vertical, horizontal or slant asymptotes for (x^2 - 5x + 6)/( x - 3) ?

Jan 25, 2017

$y = 1$, at x = 3 and $y = x - 2 , x \ne 3 \to y = x - 2$, for $x \in R$.

No asymptotes.

#### Explanation:

As $y = \frac{\left(x - 2\right) \left(x - 3\right)}{x - 3}$, we can redefine y as follows.

$y = 1$, at x = 3 and

$y = x - 2 , x \ne 3$