# How do you find the vertical, horizontal or slant asymptotes for #y=(x^2-1)/(2x^2 + 3x-2)#?

##### 1 Answer

Oct 23, 2016

The vertical asymptotes are

The horizontal asymptote is

#### Explanation:

We facorise

As we cannot divide by

So for

To look for horizontal asymptotes, we rewrite

the limit

the limit

So